Question

an object at rest attains uniform acceleration of 5m/s what will be its velocity at the end of 2m

Answer 1

Answer:

thank u

Explanation:

Answer 2

The initial velocity travelled is 625m
The accleration is α=10m/s
2

The time is t=5s
Apply the equation of motion
v=u+at
The velocity is v=0+10.5=50m/s.
The distance travelled in the first 5s is
s=ut+
2
1
​
at
2

=0.5+
2
1
​
.10.5
2
=125m
Thedistancetravelledinthefollowing10sis
s
1
​
=ut
1
​
=50.10=500m
Thetotaldistancetravelledis
d=s+s
1
​
=125+500=625m