AN OBJECT AT REST IS ACCELERATED BY 5 METER PER SECOND SQUARE FOR TIME 5 SECOND WHAT WILL ME ITS KINETIC ENERGY AT THE END OF 5 SECOND
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Hey there!!
=> u = 0 m/s
a = 5m/s²
t =5 sec
Using motion equation,
=> v = u + at
Heheso
=> v = 5x5 = 25 m/s
Now kinetic energy => mass should be required...
K = 1/2 mv²
=> u = 0 m/s
a = 5m/s²
t =5 sec
Using motion equation,
=> v = u + at
Heheso
=> v = 5x5 = 25 m/s
Now kinetic energy => mass should be required...
K = 1/2 mv²
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