an object at rest start moving it covers distance 2m in 1 second . it cover further distance of 5m in 2 seconds in same directions . what is its average velocity and acceleration
Answers
Answer:
The average velocity and acceleration is 2.33 m/s and 0.77 m/s²
Explanation:
Given that,
An object covers a distance of 2 meter in 1 sec. It covers for the distance of 5 meter into second in the same direction.
The average velocity is equal to the total distance divided by the total time.
In mathematical terms,
v_{avg}=\dfrac{D}{T}v
avg
=
T
D
Where, D = total distance
T = total time
Put the value of D and T into the formula
v_{avg}=\dfrac{2+5}{1+2}v
avg
=
1+2
2+5
v_{avg}=\dfrac{7}{3}v
avg
=
3
7
v_{avg}=2.33\ m/sv
avg
=2.33 m/s
Now, The acceleration will be
Using equation of motion
v = u+atv=u+at
2.33=0+a\times32.33=0+a×3
a= \dfrac{2.33}{3}\ m/s^2a=
3
2.33
m/s
2
a=0.77\ m/s^2a=0.77 m/s
2
Hence, The average velocity and acceleration is 2.33 m/s and 0.77 m/s²