An object at rest starts moving.It covers a distance of 2 m in one second. It covers a further distance of 5 m in two seconds in the same direction.What is the average velocity and accelaration?
Answers
Answer:
average velocity = 2.3 ms^-1
average acceleration = 0.76ms^-2
Explanation:
given total distance covered = 2+5= 7m
total time taken = 3sec
average velocity = total displacement/ total time
= 7/3 => 2.33 ms^-1
average acceleration = avg velocity/ total time
avgerage acceleration = 2.33/3
= 0.77 ms^-2
Answer:
As we know,
AVERAGE VELOCITY=DISPLACEMENT/TOTAL TIME
HERE, DISPLACEMENT IS 7M BECAUSE THE BODY IS TRAVELLING IN THE SAME DIRECTION AND TOTAL TIME IS 3 SEC.
SO, AVERAGE VELOCITY IS 7/3 M/S
NOW, ACCELERATION=FINAL VELOCITY-INITIAL VELOCITY/TIME
AS WE KNOW SPEED=DISTANCE/TIME
BUT HERE MOTION IS IN STRAIGHT LINE
THEREFORE VELOCITY=DISTANCE/TIME
=5/2=FINAL VELOCITY
INITIAL VELOCITY=0
SO, ACCELERATION=(5/2-0)/2
AND THIS IS EQUAL TO 5/4 M/S
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