An object at rest starts moving.It covers a further distance of 2m in one second It covers a further distance of 5m in 2second in same direction . What is its average velocity and acceleration ?? please help
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27
As we know,
AVERAGE VELOCITY=DISPLACEMENT/TOTAL TIME
HERE, DISPLACEMENT IS 7M BECAUSE THE BODY IS TRAVELLING IN THE SAME DIRECTION AND TOTAL TIME IS 3 SEC.
SO, AVERAGE VELOCITY IS 7/3 M/S
NOW, ACCELERATION=FINAL VELOCITY-INITIAL VELOCITY/TIME
AS WE KNOW SPEED=DISTANCE/TIME
BUT HERE MOTION IS IN STRAIGHT LINE
THEREFORE VELOCITY=DISTANCE/TIME
=5/2=FINAL VELOCITY
INITIAL VELOCITY=0
SO, ACCELERATION=(5/2-0)/2
AND THIS IS EQUAL TO 5/4 M/S
AVERAGE VELOCITY=DISPLACEMENT/TOTAL TIME
HERE, DISPLACEMENT IS 7M BECAUSE THE BODY IS TRAVELLING IN THE SAME DIRECTION AND TOTAL TIME IS 3 SEC.
SO, AVERAGE VELOCITY IS 7/3 M/S
NOW, ACCELERATION=FINAL VELOCITY-INITIAL VELOCITY/TIME
AS WE KNOW SPEED=DISTANCE/TIME
BUT HERE MOTION IS IN STRAIGHT LINE
THEREFORE VELOCITY=DISTANCE/TIME
=5/2=FINAL VELOCITY
INITIAL VELOCITY=0
SO, ACCELERATION=(5/2-0)/2
AND THIS IS EQUAL TO 5/4 M/S
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0
- Explanation:
i don t know
dghsfbh
as. resery answer 2.33
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