an object at right angles to the principal axis of a convex mirror of radius of curvature 20 the image formed is 2 cm high and is 6 cm from the pole find the distance of the image from the pole and its height
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Answer:
2cm into 6cm 12cm
Explanation:
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The radius of curvature is twice the focal length. So f = 10 cm
Object distance is given as 15 cm. Use the mirror equation 1/u + 1/v = 1/f
1/15 + 1/v = 1/10
So v = 30 cm
magnification = image size / object size = image distance / object distance.
In this case magnification is v/u = 30 / 15 =2
so image size = 2 x 2 = 4cm
Since the object distance is greater than focal length, it would be a real image (as the sign suggests in above solution). Note that v would have been negative if the object distance
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