Question

an object at right angles to the principal axis of a convex mirror of radius of curvature 20 the image formed is 2 cm high and is 6 cm from the pole find the distance of the image from the pole and its height

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Answer 1

Answer:

The radius of curvature is twice the focal length. So f = 10 cm

Object distance is given as 15 cm. Use the mirror equation 1/u + 1/v = 1/f

1/15 + 1/v = 1/10

So v = 30 cm

magnification = image size / object size = image distance / object distance.

In this case magnification is v/u = 30 / 15 =2

so image size = 2 x 2 = 4cm

Since the object distance is greater than focal length, it would be a real image (as the sign suggests in above solution). Note that v would have been negative if the object distance u was less than focal length.

Explanation: