Question

An object changes its the city from 6 m/s to 4m/s when it cover a distance of 20m. Find out the acceleration of the object.

Answer 1

Answer:

v^2 - u^2 = 2as

4m^2 - 6m^2 = 2*a*20m

16m - 36m = 40 a

-20m = 40a

a = - 2

acceleration = -2m/s^2

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