Question

An object changes its velocity from 10 m/s to 20 m/s having mass 50 kg

find the work done in terms of change in kinetic energy


please answer!!!!!​

Answer 1

Given:-

• Mass of object ,m = 50 kg

• Initial Velocity ,u = 10 m/s

• Final velocity ,v = 20 m/s

To Find:-

• Work done in terms of Kinetic Energy.

Solution:-

We have to calculate the work done in terms of Kinetic Energy . Using Formula

• W = ∆KE ---------(1)

where,

W is the Work Done

∆K is the change in kinetic energy

• ∆KE = KEf - KEi ----------(2)

Where,

KEf is the Final kinetic Energy

KEi is the Initial Kinetic Energy

Substitute the value we get

From (1) & (2) we get

→ W = KEf - KEi

→ W = 1/2×m×v² - 1/2×m × u²

→ W = 1/2× 50 ×20² - 1/2× 50 × 10²

→ W = 25×400 - 25 × 100

→ W = 10000 - 2500

→ W = 7500 J

Therefore,the work done in terms of Kinetic Energy is 7500 Joules.

Answer 2

Given :-

• Initial velocity = 10 m/s
• Final velocity = 20 m/s
• Mass = 50 kg

To Find :-

Work done in terms of kinetic energy.

Solution :-

We have to calculate Kinetic energy. So the formula is

$\huge \bf W = \triangle KE ...1$

W = Work done

∆KE = Kinetic energy

$\huge \bf \triangle KE = KEf - KEi$

KEf = Final kinetic energy

KEi = Initial kinetic energy

Putting values

➟ W = ½ × 50 × 20 - ½ × 10 × 50

➟ W = 25 × 20 - 25 × 50

➟ W = 10000- 2500

Hence :-

The work done by object is 7500 Joule.