Question

An object changes its velocity from 30 ms⁻¹ to 40 ms⁻¹ in a time interval of 2s. What is its acceleration?

Answer 1

we know,
a = v - u / t
a = 40-30/2
= 10/2 =5 m / s sq.

Answer 2

⇝ Given :-

• An object changes its velocity from 30m/s to 40m/s in a time interval of 2 sec

⇝ To Find :-

• Acceleration of the Object.

⇝ Solution :-

We Have ,

• Initial Velocity = u = 30 m/s
• Final Velocity = v = 40 m/s
• Time Taken = t = 2 s.
• Let Acceleration of car be = a m/s².

★ We Have 1st Equation of Motion as :

$\begin{gathered}\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{ v = u + at }}} \\ \end{gathered}$

⏩ Putting Given Values :

$\begin{gathered}:\longmapsto \rm 40 = 30 + a \times 2 \\ \end{gathered}$

$\begin{gathered}:\longmapsto \rm 2a = 40 - 30 \\ \end{gathered}$

$\begin{gathered}:\longmapsto \rm 2a = 10 \\ \end{gathered}$

$\begin{gathered}:\longmapsto \rm a = \cancel\frac{10}{2}\end{gathered}$

$\purple{ \large :\longmapsto \underline {\boxed{{\bf a = 5} }}}$

Hence,

$\Large\underline{\pink{\underline{\frak{\pmb{\text Acceleration = 5 \: m/ {s}^{2} }}}}}$

⇝ Additional Information :-

Three Equations of Motion :

$\begin{gathered}\large \qquad \boxed{\boxed{\begin{array}{cc} \maltese \: \: \bf v = u + at \\ \\ \maltese \: \: \bf s = ut + \dfrac{1}{2}a {t}^{2} \\ \\ \maltese \: \: \bf{v}^{2} - {u}^{2} = 2as\end{array}}}\end{gathered}$