Physics, asked by yudonthelpme, 1 month ago

an object changes its velocity from 35 m/s to 10m/s in 5 seconds. Find the distance covered by it during the time interval.

Answers

Answered by RealSweetie

0

a=10-35/5 m/s²= -5 m/s²

distance=ut+1/2at²=35.(5)²+1/2(-5)25=875-125=750 m

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