Question

An object covers 10 metre distance in 3 second and then 20 metre distance in 7 second calculate average speed of the object?

Answer 1

Answer:

31314m/s or ≈3.93 m/s

Explanation:

Given: Two separate incidences were distance is covered, 20 meters in 7 seconds and 20 meters in 4 seconds.

Average velocity >> the velocity from point A to point B over time.

v¯=x2−x1t2−t1,v¯=ΔxΔt

This equation does not apply. Why, Two separate motion are cared out.

Distance(s) = rate(r) x time(t)

rate (r) = velocity

1st motion 20/7 = 267m/s

2nd motion 20/4 = 5 m/s

267m/s + 5 m/s = 767m/s

767m/s2 = 31314m/s or ≈3.93 m/s