Question

 An object covers 15 m in first second, 35 m in second and 40 m in third second. Then the average speed of the object is ________​

Answer 1

Answer:

IN 1second=15m

In 2 second =35m

In 3 seconds=45m

So,we conclude that a body covers (15+35+45)m in 3seconds

Average speed=total distance covered/total time taken

=95m/3sec

=31.66m/s

approx=32m/sec

Answer 2

Answer:

31.66m/s

Explanation:

total distance covered:

= (15+35+45)m

= 95m

Total time taken = 3s

Average speed

$= \frac{total \: distance \: covered}{total \: time \: taken}$

$= \frac{95}{3} m {s}^{ - 1}$

$= 31.66m {s}^{ - 1}$

≈ 32m

i hope this helps you