An object covers 220 km of distance in the first 5 hours and then another 280 km of distance in the next 5 hours. The average speed of the object in meter per second will be-
a) 10.66 m/s
b) 13.9 m/s
c) 15.6 m/s
d) 20.4 m/s
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Given
- The first distance covered = 220 km
- Time taken to cover first distance =5 hrs
- Second distance covered = 280 km
- Time taken to cover second distance= 5 hrs
As we know
For average speed we have
Vav: = total distance covered / total time taken
= 220+280 / 5+5
= 500/10
Average speed = 50 km/hr
Or
Average speed = 13.88 m/s = 13.9 m/s
- Option b is correct
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