Question

An object covers a certain distance in 2 minutes. If the motion is uniformly accelerated at 2m/s^2, how far the object travels after start​.
Please anyone give answer fast... it urgent..

Answer 1

$\bigstar$ Answer $\bigstar$

$\checkmark$ Given:

An object covers a certain distance in 2 minutes. If the motion is uniformly accelerated at 2 m/s²

$\checkmark$ To Find:

Distance travelled after start

$\checkmark$ Solution:

We know that,

$\star$ Equation of Motion:

$\red{\implies \boxed{\sf s=ut+\dfrac{1}{2}at^{2}}}$

Here,

• u = Initial Velocity
• t = Time
• a = Acceleration
• s = Distance

Given that,

An object covers a certain distance in 2 minutes. If the motion is uniformly accelerated at 2 m/s²

We are asked to find Distance (s)

Therefore,

• t = 2 min = 120 sec
• a = 20 m/s²
• u = 0 m/s

Substituting the values,

We get,

$\blue{\implies \sf s=0(120)+\dfrac{1}{2}(2)(120^{2})}$

$\green{\sf \implies s=120^{2} \ m}$

$\pink{\sf \implies s=14400 \ m}$

Answer 2

YOUR QUESTION :

An object covers a certain distance in 2 minutes. If the motion is uniformly accelerated at 2m/s^2, how far the object travels after start.

YOUR ANSWER :

Given :

• An object covers a certain distance in 2 minutes. If the motion is uniformly accelerated at 2 m/s².

To Find :

• Distance travelled after start.

Formula :

$\blue {\boxed{\sf s=ut+\dfrac{1}{2}at^{2}}}$

✔u = Initial Velocity.

✔t = Time.

✔a = Acceleration.

✔s = Distance.

Given that,

✔t = 2 min = 120 sec.

✔a = 20 m/s².

✔u = 0 m/s.

Calculation :

$= > s = 0(120) + \frac{1}{2} (2) ({120}^{2}) \\ = > s = {120}^{2} \: m \\ = > s = 14400 \: m$