Question

an object covers a distance of 16 km in 4s and again covers the distance of 16m in 2s . find the average speed of the object
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Answer 1

Explanation:

given

d1=16km=16000m

t1=4s

s1=d×t=16000×4=64000m/s

d2=16m

t2=2s

s2=d×t=16×2=32m/s

avg speed =s1+s2/2=64000+32/2=64032/2

=32016m/s

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Answer 2

total distance/total time.

16+16÷4+2

=32/6

= 5.33ms-1