Question

An object does free fall motion. It hits the ground after 4 seconds. Calculate the velocity of the object after 3 seconds and before it hits the ground. What can be the height it is thrown?​

Answer 1

Answer:

ANSWER: 29.4 M/S²

Explanation:

USING THE FORMULA V=U + AT

TAKING A AS GRAVITY = 9.8

U = INITIAL VELOCITY

V= FINAL VELOCITY

T=TIME TAKEN

SO, AS IT IS A FREEFALL U=0

SO,

V = 0+9.8*3

THEREFORE V = 29.4 M/S²

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Answer 2

Velocity after 3 second is:-

V=g.t

V=10m/s^2. 3s

V=30m/s

Velocity after 4 second is:

V=g.t

V=10m/s^2. 6s

V=40m/s

Hence, height is:

$h = \frac{1}{2} g.t$

h=1/2 10m/s^2. 4^2=80m

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