Physics, asked by abhinavyadav, 1 year ago

an object drooped from a cliff falls with a constant accelation of 10m/s2 find its speed 5s after it was dropped

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Answered by anushkasen2
0
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Answered by devnarayan99
1
We know...
v=u+at..... (1)
here, the object is falling from rest, so initial velocity, u=0
by (1)
v=at
or, v=10×5 m s¯¹ (as a=10 min s¯²)
or, v=50 my s¯¹ (that's the speed after 5s)
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