Question

An object dropped form a cliff falls with a contant acceleration of 10 m per second .find it's speed 5 sec after is was dropped

Answer 1

Answer:

50 m / s.

Explanation:

We know,

            v = u + at,   where symbols have their usual meaning.

Here,

      Object was dropped, which means it was initially at rest, where its velocity was 0.

     When it is dropped, acceleration is 10 m / s^2.

From above, let at that point its velocity be v.

⇒ v = u + at

⇒ v = 0 + ( 10 )( 5 )          { after 5 sec }

⇒ v = ( 10 )5

⇒ v = 50

Velocity of the object at t = 5 sec is 50 m / s.