Question

An object dropped from a cliff fall with a constant acceleration of 10m per second square find it speed 2second after it was dropped.

Answer 1

Answer:

-20m/s

Explanation:

v= u +at

u =0 (since it is dropped form rest)

a=-10

t =2

v =0-10*2

v=-20m/s

Answer 2

Answer:

20 m/s

Explanation:

An object is dropped in the sense the initial velocity = 0 m/s

The constant acceleration which you are talking about is the Gravitational acceleration (g) = 10 m/s²

here, u = 0 m/s

t = 2 sec

v = ?

a = g = 10 m/s²

We have Newton's First equation of motion

v = u + at

v = 0 + 10(2)

v = 20 m/s

Thus, after dropping the ball the final velocity obtained by the ball after 2 sec is 20 m/s

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