Question

an object dropped from a cliff falls ith a constant acceleration of 10m/s2.find its sped 5s after it was dropped?

Answer 1

First it is in rest so
initial speed = u = 0m/s
final speed = v = ?
acceleration = a = 10m/s²
time = t = 5s

a = (v-u)/t
at = v-u
at+u = v
10(5) + 0 = v
50m/s = v


so it's speed after 5 second is 50m/s

Answer 2

v=u+at
=0+10*5
=0+50
=50 m/s