Question

An object dropped from a cliff falls with a constant acceleration of 10 m/s². Find its speed 5 s after it was dropped.

Answer 1

Answer:

Answer: 50m/s

Explanation: a = u -v /t

v = u + at

v= 0+ 10*5

= 50 m/s

Answer 2

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We have,

initial velocity, u = 0 m/s

acceleration. a = 10 m/s2

final velocity, v = ?

time, t = 2 sec

v = u + at= 0 + (10) × 2= 20 m/s

So, after 2 sec, its velocity is 20 m/s.