Question

An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped.​

Answer 1

❤️Hola♣️

Given:

Acceleration = 10 m/s^2

Solution:

The initial velocity is zero as it's a free fall.

Thereby, applying "equation of motion", we can calculate the velocity after 2 seconds of fall

Thereby, applying "equation of motion", we can calculate the velocity after 2 seconds of fall.

The "first equation of motion" is to be applied that is, v = u + a t

v = 0 + a t

v = 10 × 2

v = 20 m/s

❤️#sosan

Answer 2

Answer:

50

Explanation:

V = U + at

U initial velocity = 0

V = at

a = 10, t = 5

so velocity = 10*5 = 50 m/sec