Question

An object dropped from a cliff falls with a constant acceleration of 10 m/s2. Find its speed 5 s after it was dropped.

Answer 1

Answer:

v=u+at

v=0+50m/s

displacement=50×5=250m/s

Answer 2

u=0 because when a object thrown vertically upward then its initial velocity is zero

by using 1 st equation we get

v=u +at

v=0+10×5

v=50m/s

thanks