Question

An object dropped from a cliff falls with a constant acceleration of 10m/s2. Find its speed 2s after it was dropped

Answer 1

GivEn :

• Constant Acceleration, a = 10 m/s²

• Time taken, t = 2s

• Initial velocity, u = 0 m/s

To find :

Speed(final velocity) if the object was dropped in 2s.

Solution :

We've given with the Constant Acceleration, time taken & the initial velocity. And as the final velocity is not given, we've to calculate it.

Also, we know that, For any body which accelerates from rest(inital velocity = 0), the variation of speed with respect to the time is given by :

So,

$:\implies\sf Final \: velocity = Initial \: velocity + Acceleration \times time$

$:\implies\sf Final \: velocity = 0 + 10 \times 2$

$:\implies\sf{ \boxed{ \blue{ \frak{ Final \: velocity = 20 m/s.}}}} \: \bigstar$

$\therefore$ Speed(final velocity) if the object was dropped in 2s is 20 m/s.

Answer 2

Answer:

GivEn :

Constant Acceleration, a = 10 m/s²

Time taken, t = 2s

Initial velocity, u = 0 m/s

To find :

Speed(final velocity) if the object was dropped in 2s.

Solution :

We've given with the Constant Acceleration, time taken & the initial velocity. And as the final velocity is not given, we've to calculate it.

Also, we know that, For any body which accelerates from rest(inital velocity = 0), the variation of speed with respect to the time is given by :

So,

\begin{gathered}:\implies\sf Final \: velocity = Initial \: velocity + Acceleration \times time \\ \\ \\\end{gathered}

:⟹Finalvelocity=Initialvelocity+Acceleration×time

\begin{gathered}:\implies\sf Final \: velocity = 0 + 10 \times 2 \\ \\ \\\end{gathered}

:⟹Finalvelocity=0+10×2

\begin{gathered}:\implies\sf{ \boxed{ \blue{ \frak{ Final \: velocity = 20 m/s.}}}} \: \bigstar \\ \\ \\\end{gathered}

:⟹

Finalvelocity=20m/s.

★

\therefore∴ Speed(final velocity) if the object was dropped in 2s is 20 m/s.