Question

an object dropped from a cliff falls with a constant acceleration of 10 m/s.find it's speed 5s after it was dropped.

Answer 1

Hey!

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Initial velocity of the object (u) = 0
Acceleration (a) = 10 m/s^2
Time taken (t) = 5 s
Final velocity (v) = ?

We know,

v - u = at

v - 0 = 10 × 5

v - 0 = 50

v = 50 m/s
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Hope it helps...!!!

Answer 2

hey mate
here is u r answer
u=0 (object dropped)
a= 10m/s
t= 5
v= u+at
= 0+10×5
50 m/s..