An object dropped from a cliff moves down with acceleration of 10 m/s^2 find its speed 2 seconds after it was dropped
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apply v= u + at.
u=0
a = 10 m/sec^2
t= 2 sec
v= 20 m/sec
u=0
a = 10 m/sec^2
t= 2 sec
v= 20 m/sec
max20:
Hi sis , sorry for being late. Which question are u talking about.
again someone hv answered. whenever i get time to view ur qustns , it gets answered. lol
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