an object dropped from a cliff moves down with an acceleration of 10m/s find its speed after 2 sec it was dropped
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Answered by
51
a=10 m/s
v=u+at
u=0(free fall)
v=10*2
=20m/s
v=u+at
u=0(free fall)
v=10*2
=20m/s
Answered by
21
Answer: we know that
V=u+at (here acceleration is given
10 m/s2)
V=(0+10×2) m/s
V=(0+20) m/s
V=20m/s
Explanation: when the object will initially in hand its initial velocity will be zero
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