an object dropped from cliff falls with a constant acceleration of 10m/s2 find its speed after 2s after it was dropprd
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Given :
u = 0 m/s
a = 10 m/s^2
t = 2 s
To find : v after 2s
Solution :
As v = u + a t
so, v = 0 + 10×2 = 20 m/s
So, after 2s of dropping it will have speed of 20 m/s.
u = 0 m/s
a = 10 m/s^2
t = 2 s
To find : v after 2s
Solution :
As v = u + a t
so, v = 0 + 10×2 = 20 m/s
So, after 2s of dropping it will have speed of 20 m/s.
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