Question

An object drops from the edge of the roof. It passes a window 4m high in 0.6 sec. How far is the roof above the top of the window?​

Answer 1

Answer:

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Explanation:

Height of the window (h) = 2m

Acceleration due to gravity g=9.8 m/s2

Time taken (t) = 0.1 s

The velocity of the stone when it reaches the top of the window is to be calculated.

Applying the second equation of motion,

h=ut+12at2

 2 = 0.1 u + 0.049

 0.1 u = 1.951

 U = 19.51 m/s

Thus, the velocity 19.51 m/s will be the final velocity of the stone when it is covering the distance between the roof and the window.

Initially the stone is at rest i.e., u = 0

v2−u2=2gh

(19.51)2=19.6h

⇒h=19.42m

Distance between the roof and the window = 19.42 m.