An object droupped from a cilff fall water a constant acceleration of 10 m/s2. find it speed 5 s after it was dropped
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From Newtons 1st Law of Motion; v = u + at
Given that the object was initially dropped from the cliff it implies it's initial velocity u = 0
a = 10 m/s2 t = 5 s
Thus, v = (0 m/s) + [( 10 m/s2).( 5 s)]
.: v = 50 m/s
Explanation:
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