Question

An object exhant force in a cross section of 30 m2 is 5.8 N What is the pressure given by the object? please explain step By step
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Answer 1

$\large{\underline{\underline{\mathfrak{Answer :}}}}$

• Pressure Exerted is 0.194 Pa

$\underline{\underline{\mathfrak{Step-By-Step Explanation :}}}$

$\bf{Given} \begin{cases} \sf{Area\ of\ cross\ section\ (A)\ =\ 30\ m^2} \\ \sf{Force\ =\ 5.8\ N} \\ \sf{Pressure\ exerted\ (P)\ =\ ?} \end{cases}$

Use Formula for Calculating value of Pressure Exerted :

$\longrightarrow \sf{Pressure\ =\ \dfrac{Force}{Area}} \\ \\ \longrightarrow \sf{Pressure\ =\ \dfrac{5.8}{30}} \\ \\ \longrightarrow \sf{Pressure\ =\ \dfrac{58}{300}} \\ \\ \longrightarrow \sf{Pressure\ =\ 0.19 \bar{3}} \\ \\ \longrightarrow \sf{Pressure\ \approx\ 0.194\ Pa} \\ \\ \underline{\underline{\sf{Pressure\ exerted\ is\ 0.194\ Pa\ (approx.)}}}$

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Additional Information :

• Pressure is defined as Force per unit area.

• Pressure is a scalar quantity.

• SI unit of pressure is Pascal (Pa)

• Pa = N/m²

Answer 2

$\huge\underline{\orange{\frak{answer}}}$

$\sf Force = 5.8N$

$\sf Area = 30 {m}^{2}$

$\sf Pressure = \frac{force}{area}$

$\sf Pressure = \frac{5.8}{30}$

$\sf Pressure = \frac{5.8}{30}$

$\sf Pressure = 0.193333333$

$\therefore\sf\red {Pressure = 1.94~Pa}$