Question

An object experiences a constant acceleration
20 s after starting from rest. If it travels a distan
x, in the first 10 s and distance x in the remaini
10 s, then which of the following is true?
(1) X. = 2x
(4) x2 = 3x,
(2) x = x2
(3) x
-
3X2​

Answer 1

Answer:

for constant acceleration

s= 1/2 at2

for 1st 10 sec x = 1/2×a×100a

for 20 sec s = 1/2×a×400a

for 2nd 10 sec = s - x = 300a

X2=3x1

Answer 2

Answer:

Plz mark brainiest

Explanation:

let constant acceleration is a

distance travels in 20 seconds 

s = 0*20+a*20²/2

s = 200a -------------(1)

distance travels in first 10 seconds 

s1 = 0*10+a*10²/2

s1 = 50a -----------------(2)

distance travels in next 10 seconds 

s2 = s-s1

s2 = 200a-50a = 150a ----------------(3)

s2/s1 = 150a/50a = 3