Question

An object falling freely from rest reaches ground in 4second. If acceleration due to gravity is 9.8 m/ sq sec, the velocity of the object on reaching the ground will be​

Answer 1

✬ Velocity = 39.2 m/s ✬

Given:

• Initial velocity of object is 0 m/s. (rest)
• Time is 4 seconds.
• Acceleration due to gravity is 9.8 m/s².

To Find:

• What is the velocity of object on reaching ground ?

Formula to be used:

• v = u + gt

Solution: Let v be the velocity of object on reaching ground.

Here we have

• v = ?
• u = 0 m/s
• t = 4 seconds
• g = 9.8 m/s²

Put the values on formula

$\implies{\rm }$ v = u + gt

$\implies{\rm }$ v = 0 + (9.8)(4)

$\implies{\rm }$ v = 0 + 39.2

$\implies{\rm }$ v = 39.2

Hence, the velocity of the object on reaching the ground will be 39.2 m/s.

Answer 2

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