Question

An object falls a distance H in 50 s when dropped on the surface of the earth. How long would it take for
the same object to fall through the same distance on the surface of a planet whose mass and radius are twice
that of the arth? (neglect air resistance​

Answer 1

Explanation:

g=

r

2

GM

g

′

=

(2r)

2

G2M

=

4r

2

2GM

g

′

=

2

g

H

H

=

2

1

g

p

t

p

2

2

1

g

e

t

e

2

g

p

×t

p

2

=g

e

×t

e

2

2

g

e

t

p

2

=g

e

×50×50

t

p

2

=2×50×50⇒t

p

=

5000

=70.7sec