An object falls from a hovering helicopter and hits the ground at a speed of 30 m/s. How long does it take the object to reach the ground and how far does it fall? Sketch a velocity–time graph for the object
Answers
Answered by
5
u = 0m/s
v = 30m/s
g = 9.8m/s^2
g = (v-u)/time
9.8 = (30)/t
9.8t = 30
t = 30/9.8
t = 3.06s
v = 30m/s
g = 9.8m/s^2
g = (v-u)/time
9.8 = (30)/t
9.8t = 30
t = 30/9.8
t = 3.06s
Answered by
0
Answer: 3s
Explanation: u= 0m/s
v= 30m/s
g= 10m/s^2
g= (v-u)/time
10= 30/t
10t= 30
t= 30/10
t= 3s
Similar questions