An object falls from rest with an acceleration of g.The uncertainty in the value of the time is 6℅ and the uncertainty in the value of g is 4℅ the best estimate for the uncertainty of the position of the object is
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Let the position of object is h
time taken to reach the ground is t
object falls from height h ,
initial velocity , u = 0
use formula , S = ut + 1/2 at²
here, S = -h , u = 0, a = -g
then, -h = 0 - 1/2 ×gt²
h = 1/2 gt²
hence, expression is h = 1/2 gt²
so, to find error ,
% error in h = % error in g + 2 × % error in t
given, % error in g = 4 %
% error in time , t = 6 %
so, % error in h = 4 + 2 × 6 = 4 + 12 = 16%
hence, uncertainty of the position of the object is 16%
time taken to reach the ground is t
object falls from height h ,
initial velocity , u = 0
use formula , S = ut + 1/2 at²
here, S = -h , u = 0, a = -g
then, -h = 0 - 1/2 ×gt²
h = 1/2 gt²
hence, expression is h = 1/2 gt²
so, to find error ,
% error in h = % error in g + 2 × % error in t
given, % error in g = 4 %
% error in time , t = 6 %
so, % error in h = 4 + 2 × 6 = 4 + 12 = 16%
hence, uncertainty of the position of the object is 16%
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Given:
Acceleration = g
The uncertainty in the value of the time = 6℅
The uncertainty in the value of gravity = 4℅
To find:
The best estimate for the uncertainty of the position of the object
Solution:
Consider,
The object falls from a height h for the time t and reaches the ground.
According to the laws of motion,
Initial velocity = 0
Distance travelled = Initial velocity * Time + 1/2 * Accelration due to gravity * Time taken^2
Here,
Distance traveled = 0
Initial velocity = 0
Gravity is negative
Then,
Position = 1/2 * Accelration due to gravity * Time taken^2
To find the error,
% Error in position = % Error in gravity + 2 * % error in Time taken
4 + 2 × 6
Uncertainty in position= 16 %
Therefore, the uncertainty of the position of the object is 16 %.
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