Question

. An object falls with an acceleration of 9.8m/s2 , from height of 250m. Calculate the velocity with which he reaches the ground

Answer 1

Answer:

Given ,

a = 9.8 m/s2

u = 0

S = 250

v² = u² + 2aS

    = 2×9.8×250

v = √4900

  = 70 m/s

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