. An object falls with an acceleration of 9.8m/s2 , from height of 250m. Calculate the velocity with which he reaches the ground
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Answer:
Given ,
a = 9.8 m/s2
u = 0
S = 250
v² = u² + 2aS
= 2×9.8×250
v = √4900
= 70 m/s
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