An object fell from the third floor.
Time taken for object to reach floor is
4 second.
A) determine velocity of an object when hitting the ground
B) Calculate height of the third floor.
Answers
Answered by
0
A) Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground.
4s*9.8m/s^2
Velocity= 39.2m/s
B)let distance be d
d/t=v
d/4s=39.2m/s
d= 39.2m/s*4s
d= 156.8m
Therefore height of third floor is 156.8m
Answered by
0
acceleration =9.8m/s^2
V=?
U=0m/s
t=4sec
a=(v-u)/t
9.8=(v-u)/4
9.8×4=v
39.2m/s=v
diatance=v/t
s=39.2×4
s=156.8m
V=?
U=0m/s
t=4sec
a=(v-u)/t
9.8=(v-u)/4
9.8×4=v
39.2m/s=v
diatance=v/t
s=39.2×4
s=156.8m
Similar questions