Physics, asked by thomaskawi04, 1 year ago

An object floats in a liquid of density 1.2*10kg/m^3 with one quarter of volume above the liquid surface. You are required to determine the density of the object.

Answers

Answered by senthurkumaran2004

8

Answer:

Explanation:

Vb = Do/Dl * Vo.

3/4 = Do/1.2 * 1.

4Do = 3.6,

Do = 0.9kg/m^3. = Density of the object.

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