An object from rest travels 50m in 5 seconds with uniform acceleration. What will be the velocity of the object after 15 seconds
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Answer:
From s=ut+
2
1
at
2
In first 2 s,
s=20m
20=
2
1
a(2)
2
=2a
a=10 m/s
2
Velocity at the end of 2 s is
v=u+at=0+10×2=20m/s
In next 4s, s=ut+
2
1
a
′
t
2
160=20×4+
2
1
a
′
(4)
2
80=8a
′
a
′
=10 m/s
2
It shows that acceleration is uniform. From v=u+at
v=0+10×7=70 m/s
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Explanation:
First We Will Find The Acceleration By Given Information
Then We Will Find Velocity After 15 Seconds By Using First Equation Of Uniformly Accelerated Motion
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