Question

An object from the bridge falls, at the end of 3rd second of motion its velocity is?
a) 2 m/s
b) 10000 mm/s
c) 3000 cm/s
d) 10 m/s​

Answer 1

Answer:

Using the following, v is velocity [m/s], u is the initial velocity, a is the acceleration [m/s^2] and t is time [s], then (if we use a =-g = 9.8 [m/s^2]):

v = u + at

= 0 + 9.8*3 = 29.4 [m/s]

Using an approximate g = 10 the velocity would be about 30 [m/s]

Hope this will help you

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Answer 2

Answer:

c) 3000 cm/s

Explanation:

Initial velocity (u) = 0 m/s

Time (t) = 3 s

Acceleration (a) = g = 10 m/s2

Final velocity (v) = ?

Using the 2nd equation of motion-

v = u + at

so, v = 0 + 10 m/s2 * 3 s

v = 30 m/s = 3000 cm/s