An object gets 20 second to increase the speed from 10m/s to 50m/s. If the mass of the object is 1000 kg, what force will be required to do so?
Answers
Answered by
2
f=ma
m=1000kg=1000000g
u=10m/s
v=50m/s
t=20
a=(v-u)/t
=(50-10)/20
=2m/s^2
f=1000000*2
=2000000N
m=1000kg=1000000g
u=10m/s
v=50m/s
t=20
a=(v-u)/t
=(50-10)/20
=2m/s^2
f=1000000*2
=2000000N
Answered by
1
50 = 10 + 20a
40 = 20a
a = 2 m/s²
F = ma
= 1000*2
F = 2000N
40 = 20a
a = 2 m/s²
F = ma
= 1000*2
F = 2000N
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According to the question:
Initial velocity (u) = 10m/s, final velocity (v) = 50m/s, time (t) = 20 second, Mass (m) = 1000 kg,
Therefore, force (F)=?
⇒ 20 kg ×40 ms-2 ⇒800 kgms-2 or 800 N
Thus required force = 800 N