an object going down in inclined plane at the acceleration of 5 m/s . find the velocity 3 s after start .
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Answered by
2
given that ,
u = 0
time = 3s
acceleration = 5 m/s²
v = ?
= u + at
= 0 + 5 * 3
= 15 m/s ( answer )
u = 0
time = 3s
acceleration = 5 m/s²
v = ?
= u + at
= 0 + 5 * 3
= 15 m/s ( answer )
Answered by
0
equation of motion in single dimension:
v = u + a t
initial velocity = u = 0 as the object started fro m rest.
a = acceleration = 5 m/sec/sec
t = 3 seconds
v = 0 + 5 * 3 = 15 meters/sec
the direction of this velocity is along the inclined plane. as it is a vector, we need to mention the direction also.
v = u + a t
initial velocity = u = 0 as the object started fro m rest.
a = acceleration = 5 m/sec/sec
t = 3 seconds
v = 0 + 5 * 3 = 15 meters/sec
the direction of this velocity is along the inclined plane. as it is a vector, we need to mention the direction also.
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