Physics, asked by koushiksharma2813, 6 months ago

An object going vertical upward from the surface of the earth, having an initial velocity equal to the ............ , escapes the gravitational force of the earth

Answers

Answered by saabir24
0

Answer:

An object going vertical upward from the surface of the earth, having an initial velocity equal to the escape velocity , escapes the gravitational force of the earth

Explanation:

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Answered by naveenjai2004
0

ESCAPE VELOCITY (11.19 km/s)

An object going vertical upward from the surface of the earth, having an initial velocity equal to the ESCAPE VELOCITY (11.19 km/s), escapes the gravitational force of the earth​

Explanation:

escape velocity is the minimum speed needed for an object to escape from the gravitational influence of a massive body like earth .

Escape velocity Ve is a function of the mass of the body and distance to the center of mass of the body.

Ve=  √(2GM/R)

G is the universal gravitational constant (G ≈ 6.67×10⁻¹¹ m³/kgs²),

M the mass of the body to be escaped from ( mass of earth in case of earth)

6 × 10²⁴ kg

R the distance from the center of mass of the body to the object ( Radius of earth  on surface of earth ) = 6400 km

Ve=  11.19 km/s

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