An object hangs from a spring balance. The spring balance indicate 30n in air and 20n when the object is submerged in water. What does the balance indicate when the object is submerged in a liquid with a density that half that of water.
Answers
The balance that indicates when the object is submerged in a liquid with a density that half that of water is shown below:
Explanation:
The spring balance indicate 30n in air.
So therefore,
Fb = W − Wa
ρwVg = 30 − 20
V = 10/ρwg
The spring balance indicate 20n when the object is submerged in water.
So, in liquid :
ρw/2 . Vg = 30 − Wab
Wab = 30 − ρw/2 . ( 10g/ρwg )^5
= 25 N
For more:
A body of density d floats half immersed in liquid . Will a body of same dimensions but density 2d float in it?
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A body of mass 2kg and density 8000kg per metre cube is completely dipped in a liquid of density 800kg per metre cube. Find the force of buoyancy on it.
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Answer:
25 N
Explanation:
buoyant force= Wa-Ww=10 density of water ×v×g = 10 , v = 10 / density of water × g density of water/2 ×v×g =30- Wab Wab= 30 - density of water /2 ×v×g = 30- Wab 30-5 = 25