Question

an object has 15g at it and 9g in water. find out the amount of water displaced by the object​

Answer 1

Answer:

15g of an object, density 0.9g/ml

So, the volume of the object is v = m/ρ where m is the mass and ρ is the density.

In this case, v = 15g/0.9g/ml = 16.67ml

In order to float, the object must displace 15g of water, which means that the object floats with 16.67 – 15 = 1.67ml above the waterline.

But the question that was posed is “Will 15 grams of an object with a density of .9g/mL sink or float in 10 grams of water?”

So, the answer is that it will not float, because there is not enough water to float it: 15g are required and only 10g are present.

Have a great day☺☺☺

Answer 2

Answer:

6g Water

Explained:-

Amount of water displaced= Weight of Solid in air - Weight of Solid in Water

= 15-9

= 6 grams

:. 6 grams water is displaced