Question

An object has a constant momentum of 2.45x10^2 kg m/s. Determine the momentum of the object if its mass decreases to 1/3 of its original value and velocity increases 4 times. Deternine the momentum

Answer 1

Given,
momentum(p) = mass× velocity= 245 kg m/s.
Now, mass decreases to 1/3 of its original value &
velocity becomes 4 times.
therefore , new momentum p'=1/3 mass×4× velocity
=4×1/3×mass× velocity
=4/3×p=4/3×245
= 326.666667kg m/s.

Answer 2

Answer:

Explanation:

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