Question

An object has a kinetic energy of 14 J and a mass of 17 kg , how fast is the object moving?

Answer 1

kinetic energy = 1/2m v^2 = 14j

1/2 × 17 v^2 = 14j

v^2 = 14 × 2/17

v = 1.28 m/s. approx.

Answer 2

Answer:

The object is moving with an velocity of 1.28m/s

Explanation:

Given that,

The kinetic energy of the object is $K.E=14J$ and

The mass of the object is $m=17kg$

We are required to find the velocity of the moving object.

The kinetic energy of an object is half of the product of mass and square of velocity with which the object moves.Hence,we write

$K.E=\frac{1}{2}mv^{2}$

Substituting the given value in the above relation,we get

$14=\frac{1}{2} (17)v^{2}= > v=\sqrt{\frac{28}{17} } =1.28m/s$

Therefore,the object is moving with an velocity of 1.28m/s

#SPJ2