Question

An object has a uniform acc of 3m/s^2 . At a certain time velocity is 10m/s . What was it's velocity 2 seconds earlier? ​

Answer 1

Answer:

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Explanation:

The equation of motion to be used here is v = u + at

u : initial velocity

a : acceleration

t : time of motion

v : velocity at the end of t second.

u = v - at

u =10 - 3*2

u =10 - 6 = 4 m/s

Velocity at the start is 4 m/s